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What is the theta of the following summation: 1^3 + 2^3 + 3^3+ ... +i^3+ ......

What is the theta of the following summation: 1^3 + 2^3 + 3^3+ ... +i^3+ ... + N^3

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Answer #1

formula for sum of cubes of first n natural numbers is = (n(n+1)/2)2.

= ((n2 + n)/2)2

= (?(n2))2

= (?(n4))

Answer: ?(n4)

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