What is the theta of the following summation: 1^3 + 2^3 + 3^3+ ... +i^3+ ......

Question

Question

What is the theta of the following summation: 1^3 + 2^3 + 3^3+ ... +i^3+ ... + N^3

Answer 1

Answer #1

formula for sum of cubes of first n natural numbers is = (n(n+1)/2)².

= ((n² + n)/2)²

= (?(n²))²

⁼ (?(n⁴))

Answer: ?(n⁴)

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Answer 2

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