Please explain why x = x + 1 is Theta(nlgn)
code:
i = n;
while (i > 1)
{
i = floor(i/2);
x = x + 1;
}
why is is theta(nlgn)?
Θ notation :
It is a best case complexity so it find exact time consuming .
From the question:
i = n; // It assign only once so its complexity is Θ (1)
while (i > 1) // Number of times the loop iterate is purely
depend on the i value.
{
i = floor(i/2); // let n=13 then i values are 13,6,3,1(Since we use floor) and the value are exponentially decreased so its complexity is Θ (logn) so while loop complexity is Θ (logn)
x = x + 1; // Its complexity is logn.
}
Therefore the overall complexity is Θ(logn)
Note:
Small wrong in the question the complexity is Θ(logn).
Any doubts leave a comment
Please explain why x = x + 1 is Theta(nlgn) code: i = n; while (i...
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def plusThetaeigenket(theta):
return np.array([np.cos(theta/2),np.sin(theta/2)])
print("|+theta> = ",plusThetaeigenket,"\n")
def minusThetaeigenket(theta):
return np.array([-np.sin(theta/2),np.cos(theta/2)])
print("|-theta> = ",minusThetaeigenket,"\n")
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