Homework Answers
here,
mass of the block , m = 1000 kg
at time instant t1
equating the foces horizontally
F1 *cos(80) - F2 *cos(60) = 0 ...(1)
equating the forces vertically
F1*sin(80) + F2*sin(60) - 1000*9.8 = 0 ...(2)
from equation (1) and (2)
F1 = 7623.05 N
F2 = 2647.46 N
at time t2
the angle of F1 with the horizontal , theta1 = arctan((56.71 - 10)/(56.71/tan(80)))
theta 1 = 77.92 degree
the angle of F2 with the horizontal , theta2 = arctan((17.32 - 10)/(17.32/tan(60)))
theta2 = 36.2 degree
equating the foces horizontally
F1 *cos(77.92) - F2 *cos(36.2) = 0 ...(1)
equating the forces vertically
F1*sin(77.92) + F2*sin(36.2) - 1000*9.8 = 0 ...(2)
from equation (1) and (2)
F1 = 8664.71 N
F2 = 2247.11 N
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