Question

SITUATION G: A mast (weight 140N) has a hinged support at A. in addition it is supported by two struts. Its upper end carries a weight (130N). 10) Determine the vertical reaction at A. A.) 70 N В.) Determine the horizontal reaction at A along y. 80 N C.) 90 N D.) 100 N 11) A.) 50 N 100 N Determine the forces in the struts. В.) C.) 150 N D.) 200 N 12) A.) 322.47 N В.) 222.47 N С.) 122.47 N D.) 22.47 N SITUATION H: Two smooth spheres each of radius 150 mm and weight 250 N rest in a horizontal channel having vertical walls, the distance between which is 560 mm. 13) Find the reaction at the points of contact A as shown in the figure. A.) Find the reaction at the points of contact A as shown in the figure. A) Find the reaction at the points of contact A as shown in the figure. 222.47 222.47 В) 432.32 N С.) 501.11 N D.) 434.32 N 14) 222.47 В.) 432.32 N С.) 501.11 N D.) 434.32 N 159 С) D.) 434.32 N B.) 432.32 N 501.11 N A.)

help me please

SITUATION G: A mast (weight 140N) has a hinged support at A. in addition it is supported by two struts. Its upper end carries a weight (130N). 10) Determine the vertical reaction at A. A.) 70 N В.) Determine the horizontal reaction at A along y. 80 N C.) 90 N D.) 100 N 11) A.) 50 N 100 N Determine the forces in the struts. В.) C.) 150 N D.) 200 N 12) A.) 322.47 N В.) 222.47 N С.) 122.47 N D.) 22.47 N SITUATION H: Two smooth spheres each of radius 150 mm and weight 250 N rest in a horizontal channel having vertical walls, the distance between which is 560 mm. 13) Find the reaction at the points of contact A as shown in the figure. A.) Find the reaction at the points of contact A as shown in the figure. A) Find the reaction at the points of contact A as shown in the figure. 222.47 222.47 В) 432.32 N С.) 501.11 N D.) 434.32 N 14) 222.47 В.) 432.32 N С.) 501.11 N D.) 434.32 N 159 С) D.) 434.32 N B.) 432.32 N 501.11 N A.)

Answer 1

FeD of ot tan a- sin 150-20 NJ N2 2 Fy o N25in30- 250 250 N ZEEO N2cos30= N NE 433.0127 N FBD af 02 500 cos30 - N N3433 0/27 N Fy=o. NA-250+50osin30 N4=S00 N 500N N3 30 250 N 13 A N433.0127 N

(oordinates af ptr A(o,0,0) BCo,a,2a) c(a, 29 4a) D (a,2a,0), E(-a,2a ,0) unit vectar alang AD afta-292 1BDI Ja +(2 . 130N LE 146N iti-2A a4a-29 unit vector alang BE, uBE BE BE SG a BE

F-1302 RAE AxitAySA, A Fa40 Fap=Bp & FeE FAE UE BAXRA+ BCX Fe = 0 Ax Ay A2 24 CO. - 2a -130 -2a Ay +a A(2aAi-(a A)130o)i terms, -29 Ay+a Az 2terms AZ-2AY=130 -(D -130 a = O + BE (Ay + Az2)+140)+130)+Fp+-22) Fi +FBE J G $1 terms Fep Fac jtems Ay + F -(2) terms Az-140-130- 2F - 2 F J6 J6 AZ= 270+ F J6 -(3) Putting (2)g() in es") 270 +4F 4F JB FI-S5.7321 N 3 FTom(s), Az- 130 N Ay 70 N From (2).