Question

X Incorrect Ball 1 is launched with an initial vertical velocity v1 = 141 ft/sec. Ball 2 is launched 2.9 seconds later with an initial vertical velocity V2. Determine v2 if the balls are to collide at an altitude of 224 ft. At the instant of collision, is ball 1 ascending or descending? 11, 12 1 x 140.97 Answer: V2 = ft/sec the tolerance is +/-2% LINK TO TEXT LINK TO TEXT

help i dont know where i went wrong

Answer 1

Given Initial velocity Height reache ball 1 he v = 141 ft/s 224 ft. takes to reach height h Then using equation of h = vit bgt² motion Sign convention upward positive Downwards ative - 224=141t 4.9+2 Negative gaa9-8 m/s (downward t= 1.688 or t= 27.087s t can't be 1568 at after 2.98 another ball thrown So, t= 27.087 s Now, Time reach taken by another ball to height h t = 27.087-2.9 t = 24. 1878

Now, if & in ball 2 the initial velocity ملی then 224 = (24.12) 409 - (24.184) ولا = 12.48 4t