Question

The doubling time of a bacterial population is 20 minutes. After 100 minutes, the bacterial population was 80000. What was th

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Answer #1

a) Population after t minutes is given by

P(t) = Poekt

where Po is the initial population

Doubling time = 20 minutes

This implies

Poek(20) = 2Po

=> e20k = 2

=> ln e20k = ln 2

=> 20k = ln 2

=> k = (1 / 20) ln 2

=> k = 0.034657

Therefore,

P(t) = Poe0.034657t

Given, Population after 100 minutes = 80000

=> Poe0.034657 * 100 = 80000

=> Poe3.4657 = 80000

=> Po = 2500

Therefore,

Initial Population = 2500

P(t) = 2500e0.034657t

b) 4 hours = 240 minutes

Substituting t = 240 minutes in P(t) we get

Population after 4 hours

= 2500e0.034657 * 240

= 10239118

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