Question

The doubling period of a bacterial population is 20 minutes. At timet population was 80000. 120 minutes, the bacterial What was the initial population at timet = 0? Find the size of the bacterial population after 5 hours.

Answer 1

6 After t=5 hours t-5X GO = 300 minuty 0-03465736X 300 But) = 1250 e 10.3974077 = 1250 e = 1250 x 32768 = 40960 000 40960000

let exponentiel model is kt Bit) = Boe to duestion According t=20 minutes But) = a Bo BCD = 80000 t = 120 minutes Setting these data in equation o 2 Bo 20K - Boe 120k 80000 Boe JOK = 2 e Qok = lna ing 20 = 0.03465736 120X0.0.3465736 80000 = Bo e B. - 80000 = 1250 64 Bit) = 1250 20.034657366 BOH=1950 (a At t=0; The gniticul population wael (1950