Calculate the pH of a solution made by adding 48.0 g of sodium formate, NaHCOO, to 100. mL of 0.21 M formic acid, HCOOH. Hint what kind of solution is made? The Ka for HCOOH is 1.8 x 10-4 M. As usual, report pH to 2 decimal places.
Ka of HCOOH = 1.8 x 10^-4 M
mass of NaHCOO = 48.0 g
moles of NaHCOO = 48.0 / 68 = 0.7058
moles of HCOOH = 100 x 0.21 / 1000 = 0.021 mol
pH = pKa + log [salt / acid]
= 3.74 + log [0.7058 / 0.021]
pH = 5.27
Calculate the pH of a solution made by adding 48.0 g of sodium formate, NaHCOO, to...
Calculate the pH of a solution made by adding 35.0 g of sodium formate, NaHCOo, to 100 mL of 0.21 M formic acid, HCOOH. Hint what kind of solution is made? The K, for HCOOH is 1.8 x 10-4 M. As usual, report pH to 2 decimal places. Answer:
Calculate the pH of a solution made by adding 35.0 g of sodium formate, NaHCOO, to 100. mL of 0.21 M formic acid, HCOOH. Hint what kind of solution is made? The K, for HCOOH is 1.8 x 10-4 M. As usual, report pH to 2 decimal places. Answer:
Calculate the pH of a solution made by adding 34.0 g of sodium formate, NaHCOO, to 400. mL of 0.31 M formic acid, HCOOH. Hint what kind of solution is made? The Ka for HCOOH is 1.8 x 10-4 M. As usual, report pH to 2 decimal places.
Calculate the pH of a solution made by adding 42 g of sodium acetate, NaCH3COO, to 22 g of acetic acid, CH3COOH, and dissolving in water to make 300. mL of solution. Hint given in feedback. The K, for CH3COOH is 1.8 x 10-5 M. As usual, report pH to 2 decimal places. Answer: Calculate the pH of a solution made by adding 59 g of sodium acetate, NaCH3COO, to 22 g of acetic acid, CH3COOH, and dissolving in water...
Calculate the pH of a solution made by adding 25.0 g of sodium formate, NaHCOO, to 400 mL of 0.64 M formic acid, HCOOH Answer:
Calculate the pH of a solution made by adding 25.0 g of sodium formate, NaHCOO, to 400 mL of 0.64 M formic acid, HCOOH Answer:
Calculate the pH of a solution made by adding 25.0 g of sodium formate, NaHCOO, to 400 ml of 0.64 M formic acid, нсоон. Answer: What is the pH of pure water at 25°C? Answer: When a small amount of acid is added to a non-buffered solution, there is a large change in pH. Calculate the pH when 22.2 ml of 0.0020 M HCl is added to 100.0 mL of pure water. Comment and hint in the general feedback Answer:
23) What is the pH and percent ionization of a 0.100M solution of sodium formate (NaHCOO)? Formic acid (HCOOH) has a pKa of 3.74.
Calculate the pH of a solution that is 0.260 M in sodium formate (HCOONa) and 0.100 M in formic acid (HCOOH). Calculate the pH of a solution that is 0.500 M in pyridine (C5H5N) and 0.430 M in pyridinium chloride (C5H5NHCl). Calculate the pH of a solution that is made by combining 55 mL of 0.060 M hydrofluoric acid with 125 mL of 0.100 M sodium fluoride
Calculate the pH of a solution that is 0.290 M in sodium formate (NaHCO2) and 0.210 M in formic acid (HCO2H). The Ka of formic acid is 1.77 ⋅ 10-4.