Question

c++ programming please. thx.

Define a function template named "merge" to merge two lists of items into one list including all the items of the first list followed by the items of the second list. Even though, the data type of the items of the lists is a generic type, both input lists include items of the same type. To merge the two lists, the function first dynamically allocates enough memory to accommodate the items of both lists. The allocated memory then is filled with items of the first list followed by the items of the second list in the list of parameters. Notice that, none of the input lists will be modified during the merge process and the result of the merge is returned as a new list. Use the above-mentioned template to write a program that: 1) reads the sizes of two integer lists from the keyboard, 2) uses dynamic memory allocation to allocate memory for the requested sizes. 3) reads the integers of the lists from the keyboard, 4) calls the "merge" function to merge the input lists in a new list, 5) releases the memories allocated to the two input lists, and 6) writes all the integers included in the merged list separated by a tab character into a file named "merge.txt" Assumptions: 1. It is assumed that all the values entered by the user and all the arguments passed to the functions are valid 2. In case the file "merge.txt" is an existing file, the old content of the file is overwritten by the new content Activ Go to

Answer 1

#include <iostream>

#include <new>

#include<fstream>

using namespace std;

void merge(int p1[],int p2[],int n1,int n2)

{

int i,k;

int n3 = n1 + n2;

int * p3;

p3= new (nothrow) int[n3];

for(i=0; i<n1; i++)

  {

    p3[i]=p1[i];

  }

  for(i=0, k=n1; k<n3 && i<n2; i++, k++)

  {

    p3[k]=p2[i];

  }

ofstream ofs("merge.txt",ofstream::out);

for(int i =0;i<n3;i++)

{

ofs<<p3[i]<<" ";

}

ofs.close();

delete[] p3;

}

int main ()

{

int i,n1,n2,k;

int * p1;

int * p2;

cout << "Enter size of first list: ";

cin >> n1;

p1= new (nothrow) int[n1];

cout<<"Enter the integers included in the first list: ";

for (i=0; i<n1; i++)

{

cin >> p1[i];

}

cout << "Enter size of second list: ";

cin >> n2;

p2= new (nothrow) int[n2];

cout<<"Enter the integers included in the second list: ";

for (i=0; i<n2; i++)

{

cin >> p2[i];

}

merge(p1,p2,n1,n2);

delete[] p1;

delete[] p2;

return 0;

}

main.cpp 2 saving... 1 #include <iostream> #include <new> #include<fstream> using namespace std; void merge(int p1[], int p2[], int ni, int n2) int i,k; int n3 = n1 + n2; int * P3; p3= new (nothrow) int[n3]; for(i=0; i<n1; i++) p3[i]=p1[i]; سہی for(i=0, k=n1; k<n3 && i<n2; i++, k++) p3[k]=p2[i]; ofstream ofs("merge.txt", ofstream: :out); for(int i =0;i<n3; i++) ofs<<p3[i]<<" "; ofs.close(); delete[] p3;

int main() int i,n1, n2,k; int * p1; int * P2; cout << "Enter size of first list: "; cin >> n1; p1= new (nothrow) int[n1]; cout<<"Enter the integers included in the first list: "; for (i=0; i<n1; i++) cin >> P1[i]; cout << "Enter size of second list: "; cin >> n2; p2= new (nothrow) int[n2]; cout<<"Enter the integers included in the second list: "; for (i=0; i<n2; i++) cin >> P2[i];

merge (p1, p2, n1, n2); delete[] p1; delete[] p2; return 0; 61 }

clang version 7.0.0-3~ubuntu0.18.04.1 (tags/RELEASE 700/final) ? clang++-7 -pthread -std=c++17 -o main main.cpp ./main Enter size of first list: 5 Enter the integers included in the first list: 1 2 3 4 5 Enter size of second list: 4 Enter the integers included in the second list: 6 7 8 9

Files : merge.txt saved 1 1 2 3 4 5 6 7 8 9 main.cpp merge.txt

########################################################

Give a ThumbsUp if you found this answer Helpful :)
#######################################################

################################################################
............ Still having trouble understanding the answer ? Feel free to ask in the comment section.......