(A)Resistance of Au,Cu can be calculated as follows: AM A AAu (1.47x10 m)(1.2m) 6x10 2 6.238x10 Pata Ra Ac (1.72x10m(0.8m) 6x103 2 = 4.866x102 1RR 5.0V (6.23x10+4866x10) 45.06 A 45 A Current in both wires are same because they are is seres. u I45 A (b)Electric field in the Au,Cu can be calculated as follows AN E Au IR, AU (45.06 A) (6.238x10n) 1.2m 2.34 V/m = V EaLo IRcv La (45.06 A) (4.866x103n) 0.8m =2.74 V/m