Question

Write a program using regular expression to find the starting and ending locations of ‘fox’ in the text 'The quick brown fox jumps over the lazy dog.' Then print out its locations as follows: Found fox from (the starting location) to (the ending location).

Answer 1

import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Reg
{

     public static void main(String []args)
     {
         String data = "The quick brown fox jumps over the lazy dog";
     
         String regex = "\\bfox\\b";
        //creating an object to Pattern and passing the word to it
        Pattern pattern = Pattern.compile(regex, Pattern.CASE_INSENSITIVE);
        //creating an object to Matcher
        Matcher matcher = pattern.matcher(data);
        //checking for given word existence in given sentence
        while (matcher.find())
            {
                //It will give index of starting letter of the word
               int s=matcher.start();
               //It will give index of ending letter of the word
               int e=matcher.end();
               System.out.print("Start index: " + s);
                System.out.print(" End index: " + e + " ");
                System.out.println(matcher.group());
                //position will come if we add one to the index
                s=s+1;
                e=e+1;
                System.out.println("\nFound fox from location "+s+" to location "+e);
  
            }
      
     }
}

Note:if you have any doubts, you can ask me.