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7. (-/1 Points) DETAILS LARCALC11 11.R.037. Find sets of parametric equations and symmetric equations of the line that passes

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Answer #1
  • The vector equation of a line that passes through the points  (20, Yo, 20) and (Iz th 10) is given by :

r=ro + tū

To is the point vector of initial point

t - is a parameter

ບ. is a vector parallel to the vector formed by two points

= [20 - 21]{+ [yo – yı]] + [zo – zik

12 - 02 Th 02 Tfi – Of Ir of Ir – 0.1

T= 20, Yo, 20) + (20 – 21, yo – 41, 20 – 21

  • The parametric equation of line is given by

if:7 → be any arbitrary point such that :(zh) = 1

(12 – 0z Th – Of Tr – 02) 7 + (Oz oh oz) = (zh)

(2, 4, 2) (:20, Yo, 20) + (t [10 - 21], tyo - y1], [20 – 21])

(2, 4, 2) = (20 +t (20 - 11],yo+t (yo - y1], 20+t [20 – 21

>> I= co +t Co - 11

> y = yo +t yo – Yi

>> 2= 20 +t [20 – 21

  • The symmetric form of the equation is
  • Do +tico – 21

T1 0.0 0.0

  • y = yo +t yo – Y1

Y - Yo Yo — Yi =t

  • z = 20 + t20 – 21

Oz t 20 21

Thjerefore :

0.0 Y Yo - 20 Ir – 01 Yo — Y1 20 – 21

Given :

Two points ( 7 , 0 , 5 ) and ( 10 , 11 , 9 )

20.yo, 20) = (7,0,5)

6 ITOI) = (Tz th )

The parametric equations is given by :

  • Do +tico – 21

  = 7+t(7 – 10

r= 7 - 3t

  • y = yo +t yo – Y1

= 0 + (0 – 11)

y -11t

  • z = 20 + t20 – 21

  = 5 + +(5-9)

=5- 46

The parametric equations are:

T 7 – 31

-117

2=5 - 41

The symmetric form of equation is given by:

r= 7 - 3t

.2 - 7 t -3

y -11t

=t -11

=5- 46

t

Therefore :

- 7 2 =] y -11 2-5 5 -4 -3

Multiping whole equation by -1

y - یا 11 ته

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