14.0 2.0 10.0 equivalence point pH=7.0 8.0 6.0 4.0 2.0 0.0 0.0 20.0 40.0 6o.0 80.0...

Question

Question

Answer 1

Answer #1

This is strong acid and strong base reaction

HCl(aq)+NaOH(aq)→H2O(l)+NaCl(aq)

According to the equation the mole ratio necessary for HCl to neutralize NaOH is 1:1

we can use the equation

M1V1 = M2V2

consider M1 is the Molarity of NaOH & M2 is the molarity of HCl

we know the volume of NaOH (50 mL)

we have to calculate the volume (V2) of HCl required

50 x 0.100 = 0.200 x V2

V2 = 50 x 0.100/ 0.200

V2 = 5/0.200

V2 = 25 mL of 0.200 M HCl is required to meet the equivalence point.

Answer 2

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