V(the water deposited on 1 acre) = Number of drops X V(1
drop)
? Number of drops = V(the water deposited on 1 acre)
the "diameter" (in "number of stars wide")
10^21 / (4*10^16) = 2.5* 10^4 "stars"
area of disc = pi r^2 = 3.14* (1.25 *10^4)^2 =aprx 4.3 * 10^8
star-sq(in "number of stars-squared")
height = 10^19 / 4*10^16 = 2.5*10^2 stars high
volume = A*h = (4.3 * 10^8)*(2.5*10^2) = 10^11 stars
2)V(the water deposited on 1 acre) = Number of drops X V(1
drop)
? Number of drops = V(the water deposited on 1 acre)
Please help!! 2) Approximately how many rain drops fall on a one-acre lot during a one...
RSES Tutorial 2 (2017) The total UK electricity delivered to customers during 2014 was approximately 3 approximately 91.5% of the electrical energy available was delivered to customers, some 85% of the available electrical energy was lost in transmission and distribution 1 01.7TWh. In that year a) Determine the total electrical energy that was available (generated within the UK and net imported) during 2014. (329.7TWh) b) Determine the average UK electricity power consumed and the average UK power available over the...