1. The grey mice are camouflaged by the grey sand on the ground. They will be less noticable to the predators an this provides then more chances of survival. Thus, grey coat color has been selected by nature over the black one. The black mice are predated upon and have less chances of survival and reproduction.
2. Genetic drift is in play.
3. This has resulted in gene flow.
4. The grey coat color mice will migrate to the grey sandy
corner of the island. The microevolutionary force active here is
migration. Since the splunka bush is present
predominantly in the black area, and they are taller, the mice
which are black in color and can climb and who feed on the splunka
bush will now predominate in this region and will get selected.
Hence, natural selection comes into play at this
point.
The mice which are grey in color, and feed on moave grass will
predominate the sandy edge of the island.
5. Gene flow is active here. The splunka bushes in the mainland would soon grow into trees like those on island.
6. The allele frequency of the black coat mice which feed on the splunka bush and can climb well will increase in the volcanic ash black area of the island. The sandy edge will consist predominantly of grey coat mice which feed on moave bush and have little ability to climb. Thus, genotype frequency of these mice will increase in this area and decrease in the volcanic area.
7. The evolutionary force at work is genetic drift and natural selection. A random event such as volcanic activity wipes of the population on the ground without any bias. Those mice which had good climbing skills could climb the canopies and be safe now predominate the island, thus changing the gene frequencies. Thus, they were selected as opposed to the others for survival and reproduction.
RED EXTRA CREDIT EXERCISE: INTERACTION BETWEEN EVOLUTIONARY FORCES A species of mice inhabits a coastal plain...
In a population of mice a particular locus has two alleles A1 (dominant) and A2 (recessive). There are 126 A1A1, 167 A1A2 and 88 A2A2. Is this population in Hardy-Weinberg equilibrium (3 pts)? In a population of Gragons, there are 3151 A1A1, 1678 A1A2 and 2014 A2A2 individuals. If the environment changes so that the homozygous recessive genotype suffers a reduction of fitness where its fitness is now 0.73, but the other genotypes are unaffected, what will be the frequency...