Question

I have completed some answers! I just really really need help with the rest! I am so lost! please help me, if you can!

What information do you need? Can you see the pictures that I posted?

#2-6 are using the FIGURE from question #2

#7-8 go together and uses #7 FIGURE

#9-12 uses #9"s FIGURE but #11 and #12 compares the two FIGURES from #7&#9

#13 and 14 are together

# 15 and # 16 are their own problems

2. Construct an asymmetric methane and its mirror image as seen in figure 1. Please use the same coloring scheme or as close as possible when constructing your models. Br Br Red Bromine Gray Carbon с Green Chlorine White = Hydrogen H CI Purple = lodine I I CI asymmetric methore S configuration Bro Figure 1: Mirror imas 3. Using the molecule on the left in figure 1. draw its equivalent Fisher Projection. Assign the Absolute Configuration (R or S). R configuration * configuration Br Istill rerons І ТВсі CI I dove enterged PRODUCT H H 4. Using the molecule on the right in figure 1, draw its equivalent Fisher Projection. Assign the Absolute Configuration (R or S).

Answer 1

2)

The constructed asymmetric carbon are given below:

06 Bo Bo C C I ca 1 1 H

3)

The left one is S configuration. we have to look the molecule from the opposite side of the least priority group which is hydrogen. From that direction the order of priority 1 -2-3 is in the anticlockwise direction.

In the fischer projection, the ones on the left and right should be in front of the plane of paper. The ones on the top and bottom are to be behing the plane of paper.

By Bo 3 3) AI I min Ċ ulllel 180 H H Equivalent fischer Poojection s- configuration

4) similarly for the right structure which is R configuration.

Bo at 21 I disine I C 180 NI I Equiralent fisches projection R- Configuration

5)

After interchanging Br and Cl the structure on the left becomes identical to the structure on the right.

That is the (S) configuration is changed to (R) configuration after the interchange.

el el 5 Br I isson Cell Br A Н cl H H 20 II BO (R) IR 1 H

6)

After interchange of H and I we have the structure identical to the left one.

That is the (R) configuration again changed to (S) configuration.

el 6 HWINC my Br 7 Н Br I Dit plame rotate By go in plane Br (s) cl

7) & 8)

The structures are given below

A is (R,R) and B is (S,S)

They are enantiomers

Br Br 7. I H /NITI ce el А н Bo 8 I Br Quina 1 3 3 1 3 2 I 3 el - ice R R S S A B

9) & 10)

The structures C and D are given.

C is (S, R ) and D is (R, S )

They are enantiomers.

I Bo 11113 M 07 world I ce 19 H D

Br (10) Br 2 Milch hi 3 3 3 2 کرا 111 1!! H R S sel R s D

11) comparing A and C they are (R,R ) and (S , R )

They are diastereomers.

12) Comparing B and D they are (S,S ) and (R,S)

   They are diastereomers.

13) & 14)

Structure E and F are provided.

They are (R,S) and (S,R)

E and F are identical and are meso forms because the two asymmetric carbons are having the same substituents

13 B. of Icht, 2 3 3 Bo д R. Вх s 5 R

15)

Both structures should have similar configuration. Accordingly the fishcher projction is drawn.

044 Въ (s) Bo z IR) A ОН IN! H (S) F el S R 5 CH CH3