ZuoTi.Pro
Question

Calculate Ecell for the system when [Ag+]anode = 0.9 M and [Ag+]cathode = 1.7 M at...

Calculate Ecell for the system when [Ag+]anode = 0.9 M and [Ag+]cathode = 1.7 M at room temperature (25°C).

Enter your answer with four decimal places. Include a negative sign if you believe it's required.
science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Ecell for the system

[Ag+]anode = 0.9 M

[Ag+]cathode = 1.7 M at room temperature (25°C).

Ecell = E cathode - E anode

= 1.7 - 0.9

= 0.8

0 0
Add a comment
Know the answer?
Add Answer to:
Calculate Ecell for the system when [Ag+]anode = 0.9 M and [Ag+]cathode = 1.7 M at...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25 ∘C. The...

    A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25 ∘C. The initial concentrations of Ni2+ and Zn2+ are 1.700 M and 0.120 M , respectively. The volume of half-cells is the same. Question 2 1 pts A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25°C. The initial concentrations of Ni2+ and Zn2+ are 1.700 M and 0.120 M, respectively. The volume of half-cells is the same. What is the concentration...

  • A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25 ∘C. The...

    A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25 ∘C. The initial concentrations of Ni2+ and Zn2+ are 1.700 M and 0.120 M , respectively. The volume of half-cells is the same. What is the concentration of Ni2+ when the cell potential falls to 0.457 V ? Enter your answer to 4 decimal places and in units of mM.

  • Question 2 1 pts A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode...

    Question 2 1 pts A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25°C. The initial concentrations of Ni2+ and Zn2+ are 1.700 M and 0.120 M, respectively. The volume of half-cells is the same. What is the concentration of Ni2+ when the cell potential falls to 0.443V? Enter your answer to 4 decimal places and in units of mM.

  • Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode...

    Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Ca(II) and Sc(III) Cathode: . Ca(II) Sc(III) Anode: Ca(II) Sc(III) Ecell = 0.0591 x V (b) Pb(II) and In(III) Cathode: . Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: NI(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell - V Supporting Materials Periodic Table Supplemental...

  • Part A Calculate the pH of the cathode compartment solution if the cell emf at 298...

    Part A Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.640 V when [Zn240.27 M and PH = 0.85 atm. Express your answer using two decimal places. V ΑΣφ pH =$ Figure 1 of 1 Previous Answers Request Answer Submit Switch 8.76 X Incorrect; Try Again; 2 attempts remaining Voltmeter Zn anode NO Na - H2(g) Cathode compartment (standard hydrogen electrode) NO3 Zn2 Provide Feedback Next Anode compartment NO3...

  • Use the standard reduction potential values from your chemistry data sheet to answer this question. The...

    Use the standard reduction potential values from your chemistry data sheet to answer this question. The following electrochemical cell has a potential of Ecell = 0.322 V at 298 K: Sn (s) | Sn2+ (aq) (0.025 M) || M2+ (aq) (0.010 M), M+ (aq) (0.025 M) | Pt(s) Where M2+and M+ are ions of an unknown metal. First, determine the standard potential of the anode (EA°) -0.138 V +0.138 V 0.00 V None of the above What is the value...

  • 1. Calculate the pH of the cathode compartment solution if the cell emf at 298 K...

    1. Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.610 V when [Zn2+]= 0.20 M and PH2= 0.92 atm . Express your answer using two decimal places. pH= Switch 8.76 Voltmeter 7n anode NO, Na +H (8) Cathode compartment (standard hydrogen electrode) Anode compartment NO, Zn2+ NO NO, Zn(s) —> Zn2+ (aq)+ 2e 2H+ (aq) + 2e →H(8)

  • 1--What is E°cell for the following hypothetical reaction exactly as written (in volts), given the standard...

    1--What is E°cell for the following hypothetical reaction exactly as written (in volts), given the standard electrode potential (E°) values below? X(s) + Y2+(aq) → X2+(aq) + Y(s) X2+(aq) + 2 e- → X(s)   E° = -0.69 V Y2+(aq) + 2 e- → Y(s)   E° = -2.45 V 2--In the following spontaneous voltaic cell, which of the following statements are TRUE? Select as many answers as are correct however points will be deducted for incorrect guesses. Pt(s)|H2(g)|H+(aq)|| Ag(s)|Ag+(aq) Select one...

  • 11. Consider the reaction: M + 2HO → MOg + H2 When 0.25 mol of the...

    11. Consider the reaction: M + 2HO → MOg + H2 When 0.25 mol of the metal, M, reacted with an aqueous HCI solution (the HCl is in excess), the temperature of the solutian rose because the reactian preduced 3460 1 of heat. What is o in i] ser mol of H for It is possible that your answer could be either positive or negative. If it is negative, you must include the "minus" sign. Enter your answer as a...

  • Calculate the maximum deflection of the steel shaft (E=200 GPa), if a=0.9 m and P=76 N....

    Calculate the maximum deflection of the steel shaft (E=200 GPa), if a=0.9 m and P=76 N. The shaft diameter is 25 mm. Write your answer in mm to 2 decimal places. 2 2 A B P P

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT