please use c++ programming and single dimensional
arrays to solve this problem
thank you
Answer: Hey dear student finds the solution of your query if you have any doubt feel free to ask. Thanks!!
Dear student, this program has four functions. Input, reverse, sum and display. It will take inputs of two numbers as your input function. After that call reverse function to reverse two nums, this is necessary for doing the sum of two nums. then call function addNums() this performs addition of two nums(sum process with carry as normally we add num numbers) this is boolean type function if the sum exceeds MAX_SIZE it returns false otherwise true.
C++ Code:
#include <iostream>
using namespace std;
const int MAX_SIZE = 20; //constant for size
void inputNum(int num[], int &count) //function to take
inputs numbers
{
char ch;
cin.get(ch);
while (ch != '\n' && count <
MAX_SIZE)
{
num[count] = ch - '0';
count++;
cin.get(ch);
}
}
void reverseNums(int num[], int count) //function to reverse a
number
{
int i = 0;
int j = count - 1;
while (i < j)
{
int temp = num[i];
num[i] = num[j];
num[j] = temp;
i++;
j--;
}
}
bool addNums(int num1[], int count1, int num2[], int count2,
//function to add two numbers returns true if sum size <
MAX_SIZE
int res[], int &size) //if
sum>MAX_SIZE return false
{
int sum = 0;
int carry = 0;
int i = 0;
int j = 0;
while (i < count1 && j < count2
&& size < MAX_SIZE)
{
sum = num1[i] + num2[j] +
carry;
if (sum > 9) //check for
carry
{
carry = sum /
10;
sum = sum %
10;
}
else
{
carry = 0;
}
res[size] = sum;
size++;
i++;
j++;
if(carry != 0 && size ==
MAX_SIZE)
return
false;
}
while (i < count1 && size <
MAX_SIZE)
{
sum = num1[i] + carry;
if (sum > 9) //check
carry
{
carry = sum /
10;
sum = sum %
10;
}
else
{
carry = 0;
}
res[size] = sum;
size++;
i++;
if(carry != 0 && size ==
MAX_SIZE)
return
false;
}
while (j < count2 && size <
MAX_SIZE)
{
sum = num2[j] + carry;
if (sum > 9)
{
carry = sum /
10;
sum = sum %
10;
}
else
{
carry = 0;
}
res[size] = sum;
size++;
j++;
if(carry != 0 && size ==
MAX_SIZE) //size exceed
return
false;
}
if (carry > 0)
{
res[size] = carry;
size++;
}
return true;
}
void display(int num[], int count) //display numbers and
sum
{
for (int i = count - 1; i >= 0; i--)
{
cout << num[i];
}
}
int main()
{
int num1[MAX_SIZE]; //array1 to store num1
int num2[MAX_SIZE]; //array to store num2
int res[MAX_SIZE]; //array to store sum
int count1 = 0;
int count2 = 0;
int size = 0;
cout << "Enter the first number: ";
inputNum(num1, count1); //prompts for num1
cout << "Enter the second number: ";
inputNum(num2, count2); //prompts for num2
reverseNums(num1, count1); //reverse num1
reverseNums(num2, count2); //reverse num2
bool ans = addNums(num1, count1, num2, count2, res, size); //call addNums() and returning to bool variable
if(ans) //if true display sum and numbers
{
cout << endl;
display(num1, count1);
cout << " + ";
display(num2, count2);
cout << " = ";
display(res, size);
cout << endl;
}
else //display message
{
cout << "Sum is overflow"
<< endl;
}
return 0;
}
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