Homework Answers
(a) 172
(b) 84
take ΣM at feet = 0
0.84 x 512 = 1.25 Fhands
Fhands = 344.064 N
take ΣM at hands = 0
0.41 x 512 = 1.25 Ffeet
Ffeet = 167.936 N
Assuming the body is symmetry means each hand exerts the same
magnitude of Force
F each hand = 344.064 / 2 = 172.032 N
as well the Ffoot
F each foot = 214.512 / 2 = 83.968 N
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Your answer is partially correct. Try again The figure shows a person whose weight is W...
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I am super lost on this. I got 96.94N and 191.56N and it said it
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The figure shows a person whose weight is W 700 N doing push-ups. Find the normal force exerted by the floor on (a) each hand and (b) each foot, assuming that the person holds this position. 0.410 m 0.840 m Units (a) Number Units (b) Number
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I am super lost on this. I got 96.94N and 191.56N and it said it
was wrong. :(
Ask Yor that The drawing shows a person (weight w the person holds this position. force on each hand force on each foot s74 N L1-0.842 rn, L2-0.406 m) d ng push-ups. rnd the normal force exerted by the foor oneach hand and euch foot, assur ng
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each hand and foot, assumming that the person holds this
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