In a double slit experiment with d=5*a, a=40*, compare
(as a ratio) the intensity of the third order interference maximum
with that of the zero order maximum.
the positon of the constructive interference on the screen
y = m*lambda*d/a
a = slit width
d = distance of the sreen from the slit
lambda = wave length
the position of the 3 order maximum = y =
(3*lambda*5a)/(a)
y = 15*lambda
the intensity of light on the screen other than the central
maxima
I = Io*cos^2(pi*a*y/lambda*a)
Io = intensity of the entral maxima
I / Io = cos^2(pi*a*y/lambda*d)
I/Io = cso^2(pi*a*15*lambda/lambda*5a)
I / Io = cos^2(pi*3) = 0.99
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