Question

5. Fig. 9.2 shows the geometry of a double-slit interference experiment. If the light beam is a laser beam with a wavelength of 500 nm, the slit separation is d 0.3 mm, and the distance to the screen is L-0.7m, what is the value of x at the first minimum of the interference pattern (first minimum to the x side of the central maximum)? What is the value ofx at the first maximum of the interference pattern? What is the value of x at the second interference maximum?

Answer 1

y^n Young double slit equipment x_0 is central point when we get maxima(central maxima) for maxima any point p_1 xn = ndL/d for maxima n = 1 implies x_1 = dL/d = 500 times 10^-9 times 10^0. 7/0. 3 times 10^-3 = 1166.6 times 10^- 6 = 0. 011 m rightarrow x_2 = 2dL/d = 2 times 500 times 10^- 9 times 0. 7/0. 3 times 10^-3 for first minima, xn = 12n - 12 lambda L/sd = lambda L/2d = 0. 011/2 = 0. 0056 m = 5. 5 times 10^- 3 m