for double slit inteference
the position of minima is given by y = m*lambda*R/2d
m = 1 , 3, 5 ....
for first order minima m = 1
given y = 4.8*10^-3 m
R = distance of screen from slit = 2 m
lambda = wavelength = 633*10^-9 m
d = slits seperation
4.8*10^-3 = 1*633*10^-9*2/(2*d)
d = 1.318*10^-4 m
===================
for single slit diffraction
y = m*lambda/a
here m = 6 the minima
a = slit width
4.8*10^-3 = 6*633*10^-9/a
a = 7.9125*10^-4 m
a double slit interference pattern is shown below A double slit interference pattern is shown below....
Coherent light of wavelength 633 nm from a Helium Neon laser falls on a double slit with a slit separation of 0.103 mm. An interference pattern is produced on the screen 2.56 m away from the slits. a) how far from the central maximum is the third interference maximum? b) what about the third interference minimum?
A double-slit experiment has a slit separation distance of 0.08 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits? answer choices: 0.42 m 0.63m 0.77m 0.81m 0.92
A double-slit experiment has a slit separation distance of 0.08 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits? 0.42 m 0.63 m 0.77 m 0.81 m 0.92 m
A double-slit experiment has a slit separation distance of 0.08 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits? 0.42 m 0.63 m 0.77 m 0.81 m 0.92 m
A double-slit experiment has a slit separation distance of 0.08 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits? 0.42 m 0.63 m 0.77 m 0.81 m 0.92 m
A double-slit experiment has a slit separation distance of 0.08 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits? Group of answer choices 0.42 m 0.63 m 0.77 m 0.81 m 0.92 m
A double-slit experiment has a slit separation distance of 0.08 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits? 0.42 m 0 0.63 m O 0.77 m 0.81 m 0.92 m
A double-slit experiment has a slit separation distance of 0.08 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits? O 0.42 m O 0.63 m O 0.77 m 0.81 m O 0.92 m
A double-slit experiment has a slit separation distance of 0.08 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits? a) 0.42 m b) 0.63 m c) 0.77 m d) 0.81 m e) 0.92 m
The double slit interference problem. Please show all work for part b) step by step slit interference pattern (Fig. 1) was taken using a laser under the following conditions: 1) the double-slit separation is equal to 633 ?m, and 2) the distance between the slits and screen is 3 m. a) b) Label the integer m up to ±5 on the pattern Find the wavelength of the laser used in this Fig. 1