Question

May I please know how to program this question in python step by step? Thank you

You are to write a function called arrange. Your function will reorder a given list, where even indexed elements are arranged by descending order (based on index order) from 0 to n/2 of the list and odd indexed elements arranged in ascending order from (n/2) + 1 to n 1. Your function does not need to return the list but to change the existing list passed as an argument. Please remember, if you reassign the argument variable, you no longer have access to the original list contents. n refers to the number of elements in the list Your function will modify and rearrange the list passed to the function and the order will be checked How the list is reordered: Unchanged list Index: 0 1 2 3 45 6 Data: [3, 5, 2, 8, 7, 9, e] Rearranged list Index: 6 4 2 0, 1, 3,5 Data: [e, 7, 2, 3, 5, 8, 9] 6, 4, 2, e: Descending order from to n/2 1, 3, 5: Ascending order from n/2+ 1 to n-1 Example 1 Input:[1, 2, 3, 4, 5] Rearranged: [5, 3, 1, 2, 4]

Answer 1

[0, 7, 2, 3, 5, 8, 9] 15, 3, 1, 2, 4, 5, 3, 1, 2, 4, 6] [0, 7, 2, 3, 5, 8, 9] 1 def arrange(lst): result # for knowing last odd index 5 first len(1st)-1 if 4 6- 7 8 first%2-1: first = first - 1 # having first half of the result array 10- for i in range(first, -1, -2) result.append(1st[i]) 12 13 # having second half of the result array 14 for i in range(1, len(lst), 2): 15 16 result.append(lst[i]) # printing output 18 1st-result 19 print(1st) 20 21 # sample runs! 22 arrange([3,5,2,8,7,9,0]) 23 arrange ([1,2,3,4,5]) 24 arrange ([1,2,3,4,5,6]) 25 arrange([3,5,2,8,7,9,0])

def arrange(lst): result = []    # for knowing last odd index first = len(lst)-1 if first%2 == 1: first = first - 1    # having first half of the result array for i in range(first, -1, -2): result.append(lst[i])    # having second half of the result array for i in range(1, len(lst), 2): result.append(lst[i])    # printing output lst = result print(lst) # sample runs arrange([3,5,2,8,7,9,0]) arrange([1,2,3,4,5]) arrange([1,2,3,4,5,6]) arrange([3,5,2,8,7,9,0])