Which of the following pairs of RPN, reverse Polish notation, formulas are mathematically equivalent?
(a) A B - C + and A B C
Reverse Polish notation formulas are evaluated as follows:
A B - C +
Step | Rest of the String | Instruction | Stack |
1 | A B - C + | BIPUSH A | A |
2 | B - C + | BIPUSH B | A, B |
3 | - C + | ISUB | (A - B) |
4 | C + | BIPUSH C | (A - B), C |
5 | + | IADD | ((A - B) + C) |
But for A B C we have
Step | Rest of the String | Instruction | Stack |
1 | A B C | BIPUSH A | A |
2 | B C | BIPUSH B | A, B |
3 | C | BIPUSH C | A, B, C |
We can clearly say that they are not mathematically equivalent. But instead of A B C if we have A B C + - then we can say that they are mathematically equivalent as A B C + - is (A - (B + C).
(b) A B + C − and A B C − +
For A B + C − we have
Step | Rest of the String | Instruction | Stack |
1 | A B + C - | BIPUSH A | A |
2 | B + C - | BIPUSH B | A, B |
3 | + C - | IADD | (A + B) |
4 | C - | BIPUSH C | (A + B), C |
5 | - | ISUB | ((A + B) - C) |
For A B C − + we have
Step | Rest of the String | Instruction | Stack |
1 | A B C - + | BIPUSH A | A |
2 | B C - + | BIPUSH B | A, B |
3 | C - + | BIPUSH C | A, B, C |
4 | - + | ISUB | (A, (B - C)) |
5 | + | IADD | ((A + (B - C)) |
So, we can say that they are mathematically equivalent.
(c) A B + C * and A B C + ×
For A B + C * we have
Step | Rest of the String | Instruction | Stack |
1 | A B + C * | BIPUSH A | A |
2 | B + C * | BIPUSH B | A, B |
3 | + C * | IADD | (A + B) |
4 | C * | BIPUSH C | (A + B), C |
5 | * | IMUL | ((A + B) * C) |
((A + B) * C) is equivalent to AC + BC
For A B C + × we have
Step | Rest of the String | Instruction | Stack |
1 | A B C + x | BIPUSH A | A |
2 | B C + x | BIPUSH B | A, B |
3 | C + x | BIPUSH C | A, B, C |
4 | + x | IADD | (A, (B + C)) |
5 | x | IMUL | ((A * (B + C)) |
((A * (B + C)) is equivalent to AB + AC
So, they are not mathematically equivalent.
Please comment in case of any doubt.
Hope this helps.
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