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The beam is shown in the figure below. Use the slope-deflection method. The support Ais pinned, support B is a roller, and su

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Answer:- Given data :- EI = 21537 kw-m? settlement at B = = 73 mm = 0.073 m UDL -w= 11 kN/m ; P= 91 kN deflection Method :-)

2 (21537) MBA = 91067 + [202 + VAT 3 (0.0737 010739] MBA = 4307.4 OA + 8614.8 OB +186.002 For spar BC :- MBC 35 L FEM BC + 2E

d) Member and moments :- 8614.80-1-085x103) +4307.4 (1.553x103) +20662 MAB= MAB 0 MBA = 4307-4 (-1-0852163) +8614-2 (1-553%98

35.53 XN EllkN/m Support reactions 194.707kW 2275 knom, RA= RB = RBAT RB c = 74.47 + 62-36=136-83 kN Rc = 28.64 KN 194 707 91

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