Question

Given X 2T-QM making M the subject of the equation Question 5 Not yet answered Marked out of 1.0 P Flag question we get Select one: O i. NONE OF THE OPTIONS GIVEN If 2x-1 3(3x - 5) then x- Question6 Not yet answered Marked out o 0 O i. none of the options P Flag question i. -2 17 Select one: If atbab Find -4 -9- Select one: Oi-25 O i. 7 O ii. None of the options Question 7 Not yet answered Marked out of 1.0 PFlag question 14-6 x 2 Select O i.-4 ( ii, 1/3 18(-6) Question 8 Not yet answered Marked out of 1.0 PFlag question one: O iv. none of the option given

Answer 1

Given X = 2T - QM making M the subject of the equation we get X = 2T - QM = > 2T - X M = 2T - X/Q Hence, M = (2T - X)/Q If 2x - 1 = 3(3 x - 5) then x = Therefore 2x - 1 = 3 (3x - 5) = > 2x - 1 = 9x - 15 15 - 1 = 9x - 2x 14 = 7x Therefore x = 14/7 = 2 = > x = 2 \r\n If a . b = a^2 - b, Find -4 -9 = ? Therefore -4 - 9 = (-4)^2 - (-9) {Because a b = a^2 b] = 16 + 9 = 25 Therefore -4 - 9 = 25 By using DMAS (Division Multiplication Addition and Subtraction) Rule. 14 - 6 times 2 - 18 (-6) = 14 - 6 times 2 + 3 (Division - 18 (-6) = 3) = 14 - 12 + 3 (Multiplication 6 times 2 = 12) = 17 - 12 (Addition 14 + 3 = 17) = 5 (subtraction 17 - 12 = 5)