Question

In the intervention group, 210 of 1267 girls had a pregnancy event (birth or induced abortion)

In the comparison group, 168 of 1567 girls had a pregnancy event

1. Using these numbers, prepare a contingency table like figure:

Intervention Control Total
Pregnancy Event
No Pregnancy Event
Total

2. Calculate the relative risk for pregnancy between the intervention and comparison group.

(# participants with event in exposed group/ total participants in exposed group) Probability of event in exposed group RR =

3.  Based on your calculation of the relative risk, what effect did participation in the infant simulator intervention have on pregnancy events?

4. The researchers calculated a χ2 statistic for the association between exposure to the intervention and experiencing a pregnancy event, with the following result:

                                                χ2 = 20.8

                                                p=0.000044

What are the hypothesis and the null hypothesis for the χ2 test in this scenario?

5. Write a sentence that interprets the result of the χ2 test.

6. Based on these results, can we reject the null hypothesis?


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Answer #1

1. The contingency table is prepared as follows-

Intervention

Control

Total

Pregnancy event

210

168

378

No Pregnancy event

1057

1399

2456

Total

1267

1567

2834

2. Relative risk of pregnancy = (Probability of pregnancy in the intervention group) / (Probability of pregnancy in the control group) = (210/1267) / (168/1567) = 1.5457

3. Based on the calculation of relative risk, it can be concluded that the risk of the outcome that is pregnancy events increased by 50% due to participation in the infant simulator intervention.

4. The chi-square test in this scenario is used test whether there is any association between 'exposure to the intervention and 'experiencing a pregnancy event' . The Null Hypothesis is given as, H0 : there is no association between the two given events vs the alternative hypothesis is H1 : there exists association between the two variables.

5. If the calculated chi-square value is greater than the tabulated chi-square value then we reject the null hypothesis or else we fail to reject it. Here, we consider the p-value which is 0.000044. Hence, the test is highly significant at 1% level of significance since the p-value is very very less than the alpha value of 0.01.

6. Based on these results, we reject the null hypothesis at 1% level of significance and conclude on the basis of the given information that association exists between 'exposure to the intervention' and experiencing a pregnancy event'.

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