Question

You run a laboratory experiment and you need a mixture of 100 liters containing 45% acid to conduct your project. You don’t have that mixture but you have three different acid solutions. The first acid solution contains 10% acid, the second contains 40% acid and third 60% acid. The supply of 40% acid is low so twice as much 10% solution as 40% solution must be used. How many liters of each solution should you use?

More specifically, please complete the following sentences:

You should use

………….. liters of 10% solution;

………….. liters of 40% solution;

………….. liters of 60% solution;

Answer 1

7 of PAGE NO.: Town Total mixture needed = 100 litres mixture = 45% acid DATE: ut us assume that the capacity of 10% Tecid mixed be x 40% acid mixed bey and 60% acid mixed be z. LATO - x + y + z = 100 -(i) - 10% of a + 40% of y + 60% of z = 45% of 100 10 26 t 40 y a 60 z = 45x100 Too Too 100 10 10x + 404 + 60 = 4500 - (1) from (i) and (1) - 2y + y + z = 200 Z= 100-34 - A) putting & and z. in (ii) from (111) 4 (v) 1024) + 404 +60/100-32) = 4500 204 + 404 + 6000- 1802 = 4500 - 120 y = 4500-6000 _ 71204 1500 y = Sed = 12.5 grey y = 12.5 Litres 2x12.5 = 25 litres zo 100-34 100-3x12.5 - 100-375 ZE625 liter 23 25 ye 12.5 ZE 62.5 125 12.5 462.5 litrus litres litres of 10% of 40% of 60% solution solution solution.

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