SOLUTION :
Square side = a = 3.10 cm = 0.031 m
Diagonal, d = a √2 = 0.031 *sqrt(2) = 0.04384 m
=> distance from square corner to he centre = r = d/2 = 0.04384/2 = 0.02192 m
Magnetic field created at the centre by wires carrying current 1.80 A at 4 corners of the square perpendicular to the page :
= 4 * µ0 I / (2*pi*r)
= 4 * (4*pi*10^(-7)) * 1.80 / (2*pi*0.02192)
= 6.57 *10^(-5) T in diagonal direction
So, y component of this magnetic field
= 6.57 *10^(-5) * cos(45) T
= 4.6445 *10^(-5) T (ANSWER).
The four wires that lie at the corners of a square of side a- 3.10 cm...
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