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QUESTION 6 A researcher claims that the average yearly consumption of soft drinks per person is...
In 2008, the per capita consumption of soft drinks in Country A was reported to be...
In 2008, the per capita consumption of soft drinks in Country A was reported to be 17.93 gallons. Assume that the per capita consumption of soft drinks in Country A is approximately normally distributed, with a mean of 17.93 gallons and a standard deviation of 4 gallons. Complete parts (a) through (d) below. a. What is the probability that someone in Country A consumed more than 12 gallons of soft drinks in 2008? The probability is (Round to four decimal...
In 2008, the per capita consumption of soft drinks in Country A was reported to be...
In 2008, the per capita consumption of soft drinks in Country A was reported to be 18.51 gallons. Assume that the per capita consumption of soft drinks in Country A is approximately normally distributed, with a mean of 18.51 gallons and a standard deviation of 5 gallons. Complete parts (a) through (d) below. a. What is the probability that someone in Country A consumed more than 13 gallons of soft drinks in 2008? (Round to four decimal places as needed.)...
In 2008, the per capita consumption of soft drinks in Country A was reported to be...
In 2008, the per capita consumption of soft drinks in Country A was reported to be 19.04 gallons. Assume that the per capita consumption of soft drinks in Country A is approximately normally distributed, with a mean of 19.04 gallons and a standard deviation of 5 gallons. Complete parts (a) through (d) below. a. What is the probability that someone in Country A consumed more than 11 gallons of soft drinks in 2008? (Round to four decimal places as needed.)...
In 2008, the per capita consumption of soft drinks in Country Awas reported to be 18.95...
In 2008, the per capita consumption of soft drinks in Country Awas reported to be 18.95 gallons. Assume that the per capita consumption of soft drinks in Country A is approximately normally distributed, with a mean of 18.95 gallons and a standard deviation of 4 gallons. Complete parts (a) through (d) below. a. What is the probability that someone in Country A consumed more than 13 gallons of soft drinks in 2008? The probability is (Round to four decimal places...
A nutritionist claims that the mean tuna consumption by a person is 3.2 pounds per year....
A nutritionist claims that the mean tuna consumption by a person is 3.2 pounds per year. A sample of 50 people shows that the mean tuna consumption by a person is 3.1 pounds per year with a standard deviation of 1.06 pounds. A a= 0.01 can you reject the claim? Identify the null hypothesis and alternative hypothesis: Identify the standardized test statistic z=? Find the P-value P=? Decide whether to reject or fail to reject of fail the null hypothesis
A nutritionist claims that the mean tuna consumption by a person is 3.3 pounds per year....
A nutritionist claims that the mean tuna consumption by a person is 3.3 pounds per year. A sample of 50 people shows that the mean tuna consumption by a person is 2.9 pounds per year. Assume the population standard deviation is 1.08 pounds. At a = 0.07, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. B. Ho:u> 3.3 Ha: u 53.3 A. Ho: u = 3.3 Ha:u#3.3 O D. Ho:u#2.9 Hai u = 2.9 O...
A nutritionist claims that the mean tuna consumption by a person is 3.3 pounds per year....
A nutritionist claims that the mean tuna consumption by a person is 3.3 pounds per year. A sample of 70 people shows that the mean tuna consumption by a person is 3.2 pounds per year. Assume the population standard deviation is 1.16 pounds. At a 0.07, can you reject the claim? (a) ldentify the null hypothesis and altemative hypothesis. ??, ??. ??: #3.2 ??: ??: -3.3 $3.3 ??: #3.3 D. Ho:H 3.2 ??: $3.2 ??: -3.3 Ha H3.2 (b) Identify...
This case study is about a study on coffee consumption of people that live in the...
This case study is about a study on coffee consumption of people that live in the United States. In total, 92 people were randomly selected and data was gathered regarding the annual consumption of coffee in gallons. Of these 92, 51 were females and 41 were males. You must show all work and formulas used in order to receive full credit. This includes showing all steps of the appropriate hypothesis test from the chapter notes. Round decimals in calculations to...
For a particular task given to a large population of participants, a researcher claims that the...
For a particular task given to a large population of participants, a researcher claims that the mean completion time, u, of the population is 60 minutes. To test this claim, 50 subjects are chosen at random from this population and given the task independently. The mean completion time of these 50 subjects is 59 minutes. It is known that the population standard deviation of completion times is 6 minutes. Assume that the population is normally distributed. Can we reject the...
28 A nutritionist claims that the mean tuna consumption by a person is 3.2 pounds per...
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A nutritionist claims that the mean tuna consumption by a person is 3.2 pounds per year. A sample of 50 people shows that the mean tuna consumption by a person is 3.1 pounds per year. Assume the population standard deviation is 123 pounds. Ala-0.03, can you reject the daim? (a) Identify the nul hypothesis and alternative hypothesis. A. Ho = 32 OB. Ho 531 OC, Hạ 31 H732 H> 3.1 H, 23.1 OD. Ho > 3.1 OE H 32...
In 2008, the per capita consumption of soft drinks in Country A was reported to be 17.93 gallons. Assume that the per capita consumption of soft drinks in Country A is approximately normally distributed, with a mean of 17.93 gallons and a standard deviation of 4 gallons. Complete parts (a) through (d) below. a. What is the probability that someone in Country A consumed more than 12 gallons of soft drinks in 2008? The probability is (Round to four decimal...
In 2008, the per capita consumption of soft drinks in Country Awas reported to be 18.95 gallons. Assume that the per capita consumption of soft drinks in Country A is approximately normally distributed, with a mean of 18.95 gallons and a standard deviation of 4 gallons. Complete parts (a) through (d) below. a. What is the probability that someone in Country A consumed more than 13 gallons of soft drinks in 2008? The probability is (Round to four decimal places...
A nutritionist claims that the mean tuna consumption by a person is 3.3 pounds per year. A sample of 50 people shows that the mean tuna consumption by a person is 2.9 pounds per year. Assume the population standard deviation is 1.08 pounds. At a = 0.07, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. B. Ho:u> 3.3 Ha: u 53.3 A. Ho: u = 3.3 Ha:u#3.3 O D. Ho:u#2.9 Hai u = 2.9 O...
A nutritionist claims that the mean tuna consumption by a person is 3.3 pounds per year. A sample of 70 people shows that the mean tuna consumption by a person is 3.2 pounds per year. Assume the population standard deviation is 1.16 pounds. At a 0.07, can you reject the claim? (a) ldentify the null hypothesis and altemative hypothesis. ??, ??. ??: #3.2 ??: ??: -3.3 $3.3 ??: #3.3 D. Ho:H 3.2 ??: $3.2 ??: -3.3 Ha H3.2 (b) Identify...
For a particular task given to a large population of participants, a researcher claims that the mean completion time, u, of the population is 60 minutes. To test this claim, 50 subjects are chosen at random from this population and given the task independently. The mean completion time of these 50 subjects is 59 minutes. It is known that the population standard deviation of completion times is 6 minutes. Assume that the population is normally distributed. Can we reject the...
28
A nutritionist claims that the mean tuna consumption by a person is 3.2 pounds per year. A sample of 50 people shows that the mean tuna consumption by a person is 3.1 pounds per year. Assume the population standard deviation is 123 pounds. Ala-0.03, can you reject the daim? (a) Identify the nul hypothesis and alternative hypothesis. A. Ho = 32 OB. Ho 531 OC, Hạ 31 H732 H> 3.1 H, 23.1 OD. Ho > 3.1 OE H 32...
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