Question

For a particular task given to a large population of participants, a researcher claims that the mean completion time, u, of the population is 60 minutes. To test this claim, 50 subjects are chosen at random from this population and given the task independently. The mean completion time of these 50 subjects is 59 minutes. It is known that the population standard deviation of completion times is 6 minutes. Assume that the population is normally distributed. Can we reject the researcher's claim at the 0.1 level of significance? Perform a two-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places, and round your responses as specified in the table. (If necessary, consult a list of formulas.) H 0 P The null hypothesis: The alternative hypothesis: H : | O=O OSO OZO The type of test statistic: (Choose one) The value of the test statistic: (Round to at least three decimal places.) 0+0 0o =>0 xs ? The two critical values at the 0.1 level of significance: (Round to at least three decimal places.) and Can we reject the researcher's claim that the mean completion time is 60 minutes? Yes No

Answer 1

Date Soilation! Paye- gixen that S mimutes Aailed Aest thesic Ho uls 6 minutes The alte emative Nporresio minutes The pe ot test stctistC Z-+est Statistic se ose because LDe knoE and Knalan Pepulatien 3taupdaed deviation the value a the test Statistic S9-60 - l 0 8487 Z: -178

Date Pay en 2 The tusc Caisical Nalue.s at she level ot significence +1.645 and 6u -L644 reject the rescaechee claim tDat the me.an complerien S GO miDetes Can oe time No because Z<Z 117816s wer Feeilte Rejet Nilll Grothesis