Question

Gausss law is usually written Correct In the integral for Gausss law, the vector d.A represents an infinitesimal surfa magnitude of d.A is the area of the surface element. The direction of d.A is no element, pointing out of the enclosed volume. m-) is t ere o permittivity of vacuum Part B In Gausss law, to what does dencl refer? the net charge inside the closed surface the charge residing on insulators inside the closed surface all the charge in the physical system any charge inside the closed surface that is arranged symmetrically

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Q enclosed refers to net charge enclosed inside the closed surface. For example. If 2 C and -4 C are enclosed inside the surface, q encl = 2+ (-4) = -2 C . SO OPTION A SUITS THE BEST.

Please let me know if it was helpful. Thank you!

Add a comment
Know the answer?
Add Answer to:
Gauss's law is usually written phi _E = contourintegral E vector middot dA vector = q_encl/epsilon...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 1. Use Gauss's Law , = EdA E A4 = lected - Lected to closed surface...

    1. Use Gauss's Law , = EdA E A4 = lected - Lected to closed surface dosad surface decedurece 6,6 derive and utilize the expression needed to calculate the electric field 3.45 um away from a +2e point charge (e.g., a Cae* cation) in distilled water with relative permittivity & 78.2, vacuum permittivity & = 8.854x10-27-cm', and e=1.602x10-"C. 2. Use the expression for the electric potential due to a point charge V = charge 2 . 9 4ter 418, calculate...

  • Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra...

    Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT