Question

For the beam and loading shown, draw the shear and bending moment diagrams, and determine the magnitude and location of the maximum shear and bending moment. 2 kN/m AC D 6 NT 3kN/m lm-- 1.2 m 0.6 m

Answer 1

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MB 2 kN/m (B Juud amma By 3 kN/m GKN 1.2m R 0.66 Efy=o Du + (3x1) +6 - @x19) =0 By = 6.6kN (√) downward. EMB=0 2X112x (1.6+0.6) - 6X 1.6 - 3x1x015 + MB 20

MB= 5.82 kN-m (?) (Clockwise) Mx = -2x K x 4 Spam Al Sx=-2x+ - (K=O), SA=0 (1=0), Mu=0 (x=1.2), oc=1044 KN-m (4-12), Sc=-24AN non Span CD (x from A) Selalesex Melledomie 84 - So=-281.2 +6 Mx=2x1.2x(x-016) + 6(1-1,2) S (X=102), Se + 3.6 (1=1+2), Mc = - 1044 KN-m 2 (x = 108), So= +316 (4=108), Mo = +0.72 Mazo blue spac CD at & - 2x1.2 (x-0.6) + 6(x-1.2) = 0 - 2.4x4 1.44+60-7.2=0 3.68 >5-76 x= 106 (from A) - Span DB - Sx=8x11 2 +6 + 3/8-108) Mu=- 2x1,2x (4-0.6) + 6(x-102) | 1 = 1.8, So=+3.6 kN +3(x-108) (x-1.8 a R=2.8, SB=+6.6 kN (1= 1.8), ) Moo = 0.72 kN-m (1= 2.8), MB = 5.82 KN-m coccuuuuuuuu

c) plucos 6. 6 ос) 4) (+ 9. С. 32 к • 6 м yo.gT Bu/) г се 7.

Max shear Location : Point B S_B = 6.6kN

Max Moment location : Point B M_B = 5.82 kN-m

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