Hey everyone! I need help finishing this homework please. I also need the work. Thank you!!
Hey everyone! I need help finishing this homework please. I also need the work. Thank you!!...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you very much! 1) Z- is a weak base. An 0.350 M aqueous solution of NaZ is prepared. The pH of the solution was 8.93 at 25.0°C. The Kb of Z- is: 2) The base-ionization constant of ethylamine (C2H5NH2) is 6.4 x 10-4...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you! 1) Z- is a weak base. An 0.350 M aqueous solution of NaZ is prepared. The pH of the solution was 8.93 at 25.0°C. The Kb of Z- is: 2) The base-ionization constant of ethylamine (C2H5NH2) is 6.4 x 10-4 at 25.0...
i really need help everyone thank you all dat The solution of the differential equation ? + ta + x 12 is a) arctan(-) = In +C b) arctan (™) = Iné + c d) aretan () = Inr+C c) arctan 15 = Int+C e) None of these - 12
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you! 1) At 25 °C, the Ka for formic acid (HCO2H) is 1.8 x 10-4. What is the pH of a 0.10 M aqueous solution of lithium formate (LiHCO2)? 2) What is the pH (aq., 25 °C) of this solution: adding 1.64 grams...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thanks guys! 1) Z- is a weak base. An 0.350 M aqueous solution of NaZ is prepared. The pH of the solution was 8.93 at 25.0°C. The Kb of Z- is: 2) The base-ionization constant of ethylamine (C2H5NH2) is 6.4 x 10-4 at 25.0...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you! 1) At 25 °C, the pH of a 0.15 M aqueous solution of CsZ (the cesium salt of HZ) is 10.70. What is the Ka for HZ? 2) Calculate the pH of 0.586 M anilinium hydrochloride (C6H5NH3CI) solution in water at 25...
Need help! Do I need a chart or something to help with these? thanks everyone au must show your work for all problems and the answers must be in correct form SI to SI basic unit 1) 0.0327 Mm ? m 2) 742,380.56 ? m For 3 thru 11 do the conversion in either scientific form OR decimal form-not both! YOU MUST SHOW YOUR WORK to get full credit for a correct answer SI to SI 3) 5,543 mg -?...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you guys! 1) The Ka for HCN is 4.9 ~ 10-10. What is the value of Kb for CN-? 2) Using the data in the table for 0.10 M aqueous species at 25 °C, which conjugate base below is the weakest base? Explain...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you! 1) The Ka for HCN is 4.9 ~ 10-10. What is the value of Kb for CN-? 2) Using the data in the table for 0.10 M aqueous species at 25 °C, which conjugate base below is the weakest base? Explain your...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you! 1) Using the data in the table below, which conjugate acid is the weakest acid, given that all solutions (aq., 25 °C) are 0.200 M? Explain your choice! Base Kb CIO- 3.3 x 10-7 CO3-2 1.8 x 10-4 HS- 1.8 x 10-7...