Question

A projectile is launched with an initial speed of 52.0 m/s at an angle of 32.0° above the horizontal. The projectile lands on a hillside 3.50 s later. Neglect air friction. (Assume that the +x-axis is to the right and the +y-axis is up along the page.) (a) What is the projectile's velocity at the highest point of its trajectory? 27.55 x magnitude Your response differs from the correct answer by more than 10%. Double check your calculations. m/s 44.09 X direction Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. counterclockwise from the +x-axis (b) What is the straight-line distance from where the projectile was launched to where it hits its target? 292.43 Your response differs from the correct answer by more than 10%. Double check your calculations. m X

Answer 1

(a) velocity of the projectile=v=52.0 --- angle of projection=8=32.0° horizantal component of velocity of will remian constant through out the flight=V at the highest point of trajectory, the vertical component of velocity is zero. we plug the values in hand while using the relation gives v hence at the highest point of trajectory V = v cos0=14 at the highest point of trajectory the direction of velocity is to the right along the+x axis. horizantal distance from the point of projection to the point where it hit the targer=R R=v_r=44.10 ")*3.50sec=|154.3m