What is the molarity of the solution formed by dissolving 10.0g of Ca(NO3)2 in 250 mL aqueous solution?
Molar mass of Ca(NO3)2 = 164 g/mol
mass = 10 g
Number of moles = mass / molar mass
= 10/164
= 0.061 mol
Volume = 250 mL = 0.25 L
Molarity = number of moles / volume
= 0.061/0.25
= 0.244 M
Answer: 0.244 M
What is the molarity of the solution formed by dissolving 10.0g of Ca(NO3)2 in 250 mL...
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