Question

What is the molarity of the solution formed by dissolving 10.0g of Ca(NO3)2 in 250 mL aqueous solution? 0.24 M 4.1M 25 M 0.040 M Question 18 5 pts Consider the reaction H2SOalaq)+ 2NaOH(aq) 2H20() +Na sOalaq) If 25 mL of H2sO4 was needed to react with 15 mL of 0.20 M NaOH, what is the molarity of the H2SO4(aq)? 0.060 M 17 M O024 M 0.12 M

Answer 1

1)

Molar mass of Ca(NO3)2,

MM = 1*MM(Ca) + 2*MM(N) + 6*MM(O)

= 1*40.08 + 2*14.01 + 6*16.0

= 164.1 g/mol

mass(Ca(NO3)2)= 10.0 g

use:

number of mol of Ca(NO3)2,

n = mass of Ca(NO3)2/molar mass of Ca(NO3)2

=(10 g)/(1.641*10^2 g/mol)

= 6.094*10^-2 mol

volume , V = 2.5*10^2 mL

= 0.25 L

use:

Molarity,

M = number of mol / volume in L

= 6.094*10^-2/0.25

= 0.2438 M

Answer: 0.24 M

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