Question

What is the molarity of an H2SO4 solution if 35.00 mL is exactly neutralized by 32.63 mL of 0.164 M NaOH? 2NaOH + H2SO4---> Na2SO4 + 2H20

Answer 1

2NaOH + H2SO4 → Na2SO4 + 2H2O , by observing the equation we can say that for every 1 molecule of H2SO4 neutralization we need 2 molecules of NaOH. In terms of moles(or millimoles) we can say that for every 1 mole(or millimole) of H2SO4 neutralization we need 2 moles(or millimoles) of NaOH.

For neutralization, 2*Millimoles of H2SO4 = Millimoles of NaOH

Let the Molarity of Millimoles of H2SO4 be X.

Millimoles of H2SO4 = Molarity of H2SO4* Volume(in ml) = X*35

Millimoles of NaOH = Molarity of NaOH * Volume(in ml) = 32.63*0.164 = 5.351millimoles

So, 2*Millimoles of H2SO4 = Millimoles of NaOH ⇒ 2*(X*35) = 5.351 ⇒ X = 0.0764M

Therefore molarity of H2SO4 solution is 0.0764M.