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1. [17 pts, 1/line] Modify the following code to display the binary information stored at a location in memory referred named myVar: #inciude <stdio.h> #define N 8 int main0 //Enter the number of bits here char myVar/Declare variable here int i; printf (%c, * ( (long*) &myVar) &1<<i? 1 : 0 ) ; printf (n return 0

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Answer #1 
#include <stdio.h>

#define N 8

int main() {
    char myVar = 'N';
    int i;
    for(i = N-1; i >= 0; i--)
        printf("%c", *((long *) &myVar) & 1 << i ? '1' : '0');
    printf("\n");
    return 0;
}

01001110

N\;in\;ascii\;is\;78.\;and\;78\;in\;binary\;is\;01001110

so,\;the\;output\;is\;correct

I\;didn't\;have\;to\;make\;any\;changes\;to\;the\;code.\;It's\;working\;correctly!

Please let me know if you need to me make any changes.

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