Question

(you can use any language)

Write an algorithm that works with an array of size N and shows the user the next menu:

1. Fill array.

2. Get sum of array elements

3. Get the maximum value of the array elements

4. Get the minimum value of the array elements.

5. Exit

Answer 1

Algorithm:

Step 1: START
Step 2:Initiliaze or declare required variables like i,j,N,max,min,sum.

Step 3: Read N size of the array from the user.

Step 4: Declare array with size N and using while loop show the menu to the user.

1. Fill array.

2. Get sum of array elements

3. Get the maximum value of the array elements

4. Get the minimum value of the array elements.

5. Exit

Step 5: Read any one option from the user.

Step 6: Pass option to the switch statement:

  Case 1:

using for loop from i=0 to i<N read the elements into the array and break statement at the end.

  Case 2:

Using sum variable and for loop from i=0 to i<N calculate sum as sum=sum+array[i] then display the sum and break.

Case 3:

  Using for loop find maximum value by using comparison if max<array[i] if true then max=array[i]. print max.

Case 4:

  Using for loop find minimum value by using comparison if min>array[i] if true then min=array[i]. print min.

Case 5:

Write exit(0) statement to exit from the program.

Step 7:  STOP

Source code in C++:

#include<iostream> using namespace std; /*main function*/ int main() { /*variables*/ int ch, N, i, sum=0,max=0, min; /*read size of the array*/ cout<<"Enter the size of the array: "; cin>>N; /*declare array*/ int array[N]={@}; while(1) { /*show menu to user*/ cout<<"1. Fill array\n2.Get sum of array elements"<<endl; cout<<"3. Get the maximum value of the array elements"<<endl; cout<<"4. Get the minimum value of the array elements"<<endl; cout<<"5. Exit\nChoose your option: "; /*read option from user*/ cin>>ch; /*switch case*/ switch(ch)

{ /*option 1*/ case 1: cout<<"Enter the "<<N<<" elements:"<<endl; /*read elements from user*/ for(i=0; i<N;i++) { cin>>array[i]; } cout<<"Filled"<<endl; break; /*option 2*/ case 2: sum=0; /*calculate sum*/ for(i=0;i<N;i++) { sum=sum+array[i]; } /*display sum*/ cout<<"The sum of array elements is: "<<sum<<endl; break; /*option 3*/

case 3: for(i=0; i<N;i++) { /*find max*/ if(max<array[i]) max=array[i]; } /*display maximum value*/ cout<<"The maximum value of the array elements is: "<<max<<endl; break; /*option 4*/ case 4: min=array[0]; /*find min*/ for(i=1;i<N; i++) { if(min>array[i]) min=array[i]; } /*display minimum*/ cout<< "The minimum value of the array elements is: "<<min<<endl; break;

/*option 5*/ case 5: /*exit*/ exit(0); /*default option*/ default: cout<<"Choose correct option!"<<endl; } } }

Output:

C:\Users\Kumar Reddi\Desktop\arraymenu.exe Enter the size of the array: 5 1.Fill array 2. Get sum of array elements 3. Get the maximum value of the array elements 4. Get the minimum value of the array elements 5. Exit Choose your option: 1 Enter the 5 elements: 10 20 30 40 50 Filled 1.Fill array 2. Get sum of array elements 3. Get the maximum value of the array elements 4. Get the minimum value of the array elements 5. Exit Choose your option: 2 The sum of array elements is: 150

1.Fill array 2. Get sum of array elements 3. Get the maximum value of the array elements 4. Get the minimum value of the array elements 5. Exit Choose your option: 3 The maximum value of the array elements is: 50 1.Fill array 2. Get sum of array elements 3. Get the maximum value of the array elements 4. Get the minimum value of the array elements 5. Exit Choose your option: 4 The minimum value of the array elements is: 10 1.Fill array 2. Get sum of array elements 3. Get the maximum value of the array elements 4. Get the minimum value of the array elements 5. Exit Choose your option: 5 Process exited after 21.26 seconds with return value o Press any key to continue .

Code in text format (See above images for indentation):

#include<iostream>
using namespace std;
/*main function*/
int main()
{
   /*variables*/
   int ch,N,i,sum=0,max=0,min;
   /*read size of the array*/
   cout<<"Enter the size of the array: ";
   cin>>N;
   /*declare array*/
   int array[N]={0};
   while(1)
   {
       /*show menu to user*/
       cout<<"1.Fill array\n2.Get sum of array elements"<<endl;
       cout<<"3.Get the maximum value of the array elements"<<endl;
       cout<<"4.Get the minimum value of the array elements"<<endl;
       cout<<"5.Exit\nChoose your option: ";
       /*read option from user*/
       cin>>ch;
       /*switch case*/
       switch(ch)
       {
           /*option 1*/
           case 1:
               cout<<"Enter the "<<N<<" elements:"<<endl;
               /*read elements from user*/
               for(i=0;i<N;i++)
               {
                   cin>>array[i];
               }
               cout<<"Filled"<<endl;
               break;
           /*option 2*/
           case 2:
               sum=0;
               /*calculate sum*/
               for(i=0;i<N;i++)
               {
                   sum=sum+array[i];
               }
               /*display sum*/
               cout<<"The sum of array elements is: "<<sum<<endl;
               break;
           /*option 3*/
           case 3:
               for(i=0;i<N;i++)
               {
                   /*find max*/
                   if(max<array[i])
                       max=array[i];
               }
               /*display maximum value*/
               cout<<"The maximum value of the array elements is: "<<max<<endl;
               break;
           /*option 4*/
           case 4:
               min=array[0];
               /*find min*/
               for(i=1;i<N;i++)
               {
                   if(min>array[i])
                       min=array[i];
               }
               /*display minimum*/
               cout<<"The minimum value of the array elements is: "<<min<<endl;  
               break;
           /*option 5*/
           case 5:
               /*exit*/
               exit(0);
           /*default option*/
           default:
               cout<<"Choose correct option!"<<endl;
       }  
   }
}