Question

Using Matlab

Write a program which will:
a. Accept two numbers from the user m and n
b. Define an array with the dimensions a(n,m) and fill it with random numbers in the range of -100 to 100 inclusive.
c. Provide the user the following menu from which he can select:
1. Sum of all elements in the array. Print the result.
2. Sum of the element in a row that he’ll specify. Print the result.
3. Sum of the element in a column that he’ll specify. Print the result.
4. Sum of the elements in the right diagonal. Print the result.
5. Sum of the elements in the left diagonal. Print the result.
6. The element with the minimum value in the array. Print the result.
7. The element with the maximum value in the array. Print the result.
8. The element with the minimum value in a row that he’ll specify. Print the result.
9. The element with the maximum value in a row that he’ll specify. Print the result.
10. The element with the minimum value in a column that he’ll specify. Print the result.
11. The element with the maximum value in a column that he’ll specify. Print the result.
12. Print the menu again
13. Exit from the program
d. The user can elect from the menu as any times as he wants without leaving the program.

Answer 1

Code Explanation:

• Initially input number of rows and columns as n and m
• create a matrix with size n,m and fill it with zeros by using zeros(n,m)
• Run a for loop from i=1 to n and assign each row of matrix with random integers
• display the newly created matrix with random integers
• Call the print_menu() function to print the menu.This function also returns the choice we input
• use while until choice is not equal to 13. If choice is 13 then loop breaks and program ends
• Calculate and display the appropriate results which were asked
• If choice is 1 then print sum of array. To sum alla elements in an arrya use sum(sum(A)). The inner sum(A) calculates sum of every column and forms a row vector. The outer sum calculates the sum of elements in row vector which gives sum of array elements.
• If choice is 2 we shuould calculate the sum of specified row elements . We can calculate it by using sum(A(r,:)). Here A(r,:) gives the rth row.
• If choice is 3 we should calculate the sum of specified column elements. sum(A(:,c))
• If choice is 4 sum of right diagonal is calculated sum(diag(A)). We can get right diagonal by using diag(A).
• If choice is 5 we calculate the sum of left diagonal. left diagonal is diag(flip(A))
• If choice is 6 to calculate min value in array. min(min(A)) . inner min(A) gives min of every column and forms a row vector. Then outer min() gives the min of array
• If choice is 7 Similar to 6 we use max in place of min
• If choice is 8 then calculate min of specified row. min(A(r,:))
• If choice is 9 then calculate max of specified row. max(A(r,:))
• If choice is 10 calculate min of specified column. min(A(:,c))
• If choice is 11 calculate max off specified column max(A(:,c))
• If choice is 12 print menu
• If choice is 13 exit the program

Code:

n =input("Enter n");

m =input("Enter m");

A =zeros(n,m);

for i=1:n

A(i,:)= randi([-100 100],1,m);

end

disp("The generated matrix with random integers is:\n");

disp(A);

choice = print_menu();

while(choice ~= 13)

if(choice == 1)

disp(sum(sum(A)));

elseif(choice == 2)

r = input("Enter row number");

disp(sum(A(r,:)));

elseif(choice ==3)

c = input("Enter column number :");

disp(sum(A(:,c)));

elseif(choice == 4)

disp(sum(diag(A)));

elseif(choice == 5)

disp(sum(diag(flip(A))));

elseif(choice == 6)

disp(min(min(A)));

elseif(choice == 7)

disp(max(max(A)));

elseif(choice == 8)

r = input("Enter a row number: ");

disp(min(A(r,:)));

elseif(choice == 9)

r = input("Enter a row number: ");

disp(max(A(r,:)));

elseif(choice == 10)

c = input("Enter a column number: ");

disp(min(A(:,c)));

elseif(choice == 11)

c = input("Enter a column number: ");

disp(max(A(:,c)));

elseif(choice == 12)

choice = print_menu();

elseif(choice ==13)

break

else

disp("Please enter a valid choice");

end

choice = input("select an option from menu");

end

function choice = print_menu()

disp("1.Sum of elements in the array\n");

disp("2.Sum of elements in a row\n");

disp("3.Sum of elements in a column\n");

disp("4.Sum of elements in right diagonal\n");

disp("5.Sum of elements in left diagonal\n");

disp("6.The element with minimum value in the array\n");

disp("7.The element with maximum value in the array\n");

disp("8.The element with minimum value in a row\n");

disp("9.The element with maximum value in a row\n");

disp("10.The element with minimum value in a column\n");

disp("11.The element with maximum value in a column\n");

disp("12.print the menu again\n");

disp("13.Exit from the program\n");

choice = input("Select an option from menu");

end

O/P:

Enter n

4

Enter m

5

The generated matrix with random integers is:\n
-30 66 17 10 84
-43 52 51 -24 14
-85 -90 6 56 87
-74 14 -6 -98 -33

1.Sum of elements in the array\n
2.Sum of elements in a row\n
3.Sum of elements in a column\n
4.Sum of elements in right diagonal\n
5.Sum of elements in left diagonal\n
6.The element with minimum value in the array\n
7.The element with maximum value in the array\n
8.The element with minimum value in a row\n
9.The element with maximum value in a row\n
10.The element with minimum value in a column\n
11.The element with maximum value in a column\n
12.print the menu again\n
13.Exit from the program\n
Select an option from menu

1

-26

select an option from menu

5

-103

select an option from menu

6

-98

select an option from menu

8

Enter a row number:

2

-43

select an option from menu

9

Enter a row number:

3

87

select an option from menu

12

1.Sum of elements in the array\n
2.Sum of elements in a row\n
3.Sum of elements in a column\n
4.Sum of elements in right diagonal\n
5.Sum of elements in left diagonal\n
6.The element with minimum value in the array\n
7.The element with maximum value in the array\n
8.The element with minimum value in a row\n
9.The element with maximum value in a row\n
10.The element with minimum value in a column\n
11.The element with maximum value in a column\n
12.print the menu again\n
13.Exit from the program\n
Select an option from menu

11

select an option from menu

13

>>

Code screenshot:

1 - 2 3- 4 - 5- 6 7- disp(sum(AC:,0))); untitled.mx + n =input("Enter n"); m =input("Enter m"); A =zeros(n,m); for i=1:n Ali, :)= randi([-100 100],1,m); end disp("The generated matrix with random integers is: \n"); disp(A); choice = print_menu(); while(choice <= 13) if (choice == 1) disp(sum(sum(A)); 13 - elseif (choice == 2) r = input("Enter row number"); disp(sum(A(r,:))); elseif(choice ==3) C = input("Enter column number :"); Shes 8 - 9 10 12 12 - 14 15 - 16 16 17 12 1 18 LIIIIIIIIIIII 19 - 20 2 21 - 22 - 22 23 - 24 - 25 - 26 elseif (choice == 4) disp(sum(diag(A)); elseif (choice == 5) disp(sum(diag(flip(A)))); elseif (choice == 6) disp(min(min(A))); elseif (choice == 7) disp(max(max(A)));

27 - 28 - 29 30 31 - 32 - - 33 - 34 35 - 36 - 37 - 38 - 39 elseif (choice == 8) r = input("Enter a row number: "); disp(min(A(r,:))); elseif (choice == 9) r = input("Enter a row number: "); disp(max(Ar, :))); elseif (choice == 10) C = input("Enter a column number: "); disp(min(A(:,c))); elseif (choice == 11) C = input("Enter a column number: "); disp(max(A(:,c))); elseif (choice == 12) choice = print_menu(); elseif (choice ==13) break else disp("Please enter a valid choice"); end choice = input("select an option from menu"); end function choice = print_menu() disp("1.Sum of elements in the array\n"); disp("2.Sum of elements in a row\n"); disp("3.Sum of elements in a column\n"); disp(4.Sum of elements in right diagonal\n"); 40 41 - ייייייייייייי 42 - 43 - 44 - 45 46 - 47 48 49 - 50 51 - 52 -

53 - 54 - 55 56 - 57 - disp("5.Sum of elements in left diagonal\n"); disp("6. The element with minimum value in the array\n"); disp("7. The element with maximum value in the array\n"); disp("3. The element with minimum value in a row\n"); disp(9. The element with maximum value in a row\n"); disp("10. The element with minimum value in a column\n"); disp("11. The element with maximum value in a column\n"); disp("12.print the menu again\n"); disp("13.Exit from the program\n"); choice = input("Select an option from menu"); 58 - 60- 61 - 63 - end

O/P screenshot:

Enter n 4 Enter m 5 The generated matrix with random integers is:\n -30 66 17 19 84 -43 52 51 - 24 14 -85 -90 6 56 87 - 74 14 -6 -98 -33 1. Sum of elements in the array\n 2. Sum of elements in a row\n 3.Sum of elements in a column\n 4.Sum of elements in right diagonal\n 5.Sum of elements in left diagonal\n 6. The element with minimum value in the array\n 7. The element with maximum value in the array\n 8. The element with minimum value in a row\n 9. The element with maximum value in a row\n 10. The element with minimum value in a column\n 11. The element with maximum value in a column\n 12.print the menu again\n

13. Exit from the programın Select an option from menu 1 -26 select an option from menu 5 -103 select an option from menu 6 -98 select an option from menu Enter a row number: 2 -43 select an option from menu Enter a row number:

3 87 select an option from menu 12 1. Sum of elements in the array\n 2.Sum of elements in a row\n 3.Sum of elements in a column\n 4.Sum of elements in right diagonal\n 5.Sum of elements in left diagonal\n 6. The element with minimum value in the array\n 7. The element with maximum value in the array\n 8. The element with minimum value in a row\n 9. The element with maximum value in a row\n 10. The element with minimum value in a column\n 11. The element with maximum value in a column\n 12.print the menu again\n 13. Exit from the program\n Select an option from menu 11 select an option from menu 13

(Please comment If you still have any doubts. I will definitely help)