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Given the velocity potential f of a flow, find the velocity V = Vf of the field and its value at P. f = 4x2 + 5y2 + 3z2, P: (

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te 42° +54°+372 , P:= (2,3,4) i v= f 1 =(80, 109, 62) TV= (82,104, 67) | so VCP) = V(2,3,4) - (16,30,24) (VCP) = (16,20,24)

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