How many milliliters of 11.6 M perchloric acid solution should be used to prepare 1.50 L of 0.100 M HClO4?
M1V1 = M2V2
0.100 M *1500 mL = 11.6 M*V2
150 = 11.6 V2
V2 = 150 / 11.6 = 12.93 mL solution is required.
How many milliliters of 11.6 M perchloric acid solution should be used to prepare 1.50 L...
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