Given that,
d1 = 2.5 cm
d2 = 1 cm
F = 3KN
E = 17 GPa
a = F / E x 3.14 x (d1-d2)2 x 100
= 3 x 103 / 17 x 103 x 3.14 x (25 - 10 )2 x 10
= 124.73 N /mm2
This is the normal condition,
Now, if E = 193 GPa
a1 = F / E x 3.14 x (d1-d2)2 x 100
= 3 x 103 / 193 x 103 x 3.14 x ( 25 - 10 )2 x 100
= 109.8 N/mm2
a2 = F / E x 3.14 x (d1-d2)2 x 100
= 3 x 103 / 214 x 103 x 3.14 x ( 25 - 10 )2 x 100
= 99 N/mm2
a3 = F / E x 3.14 x (d1-d2)2 x 100
= 3 x 103 / 124 x 103 x 3.14 x ( 25 - 10 )2 x 100
= 171 N/mm2
From all the above conditions, we can say that,
Co - Cr alloy is the best suitable.
(b) A hip implant in thigh bone may be modelled by concentric cylinder as illustrated in...