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The amounts of electricity bills for all households in a particular city have an approximately normal distribution with a mea

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Answer #1

Solution :

Given that ,

mean = \mu = 145

standard deviation = \sigma =28

n = 20

sample distribution of sample mean is ,

\mu\bar x = \mu

\mu\bar x = 145

sampling distribution of standard deviation

\sigma\bar x =\sigma  / \sqrt n = 28 / \sqrt 20

\sigma\bar x = 6.26=6 rounded

sampling distribution is approximately normal

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