Question

Question 9 (1 point) Saved Electricity bills in a certain city have mean $ 123.76. Assume the bills are normally distributed with standard deviation $ 18.20. A sample of 60 bills was selected for an audit. Find the 44 percentile for the sample mean. Write only a number as your answer. Round to two decimal places (for example: 42.81). Do not write any units. Your Answer: Answer

Answer 1

9)

Given that,

$\sigma$_{$\bar x$} = $\sigma$ / $\sqrt$ n = 18.20 / $\sqrt$ 60

P(Z < 0.15) = 0.44

z = -0.15

$\bar x$ = z * $\sigma$ _{$\bar x$}+ $\mu$ _{$\bar x$} = -0.151 * 18.20 / $\sqrt$ 60 + 123.76 = 123.41

44 percentile = 123.41