How many liters of 0.810 M HNO3 are needed to react with 2.9 g of Hg2Cl2?...

Question

Question

How many liters of 0.810 M HNO₃ are needed to react with 2.9 g of Hg₂Cl₂?

molar mass = 472.08 g/mol

Hg₂Cl₂ + 5HNO₃ ⟶2Hg(NO₃)₂(aq) + HNO₂(aq) + 2HCl(aq) + H₂O(l)

Answer 1

Answer #1

Ans mole of H22Cl₂ = weight Molan mass 0.00 6L mole 2.9 472.08 mole of HNO3 Molanity x Volume 0.81 x V Hq2 Cl2 + SHINO, 2 kg

Answer 2

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