Homework Answers
NH3 + Br2 ------------- NH2Br + HBr
Initial concentration of NH2Br = 0.00M . It is at zero time. i,e t= 0.0 sec
Concentration of NH2Br after 15.4 sec = 0.206M. It is at 15.4 sec i.e t = 15.4 sec
Rate of the reaction = change in concentration / time
Rate of the formation of NH2Br =( 0.206 - 0.00) / (15.4 - 0.0)
Rate of the formation of NH2Br = 0.206 / 15.4 = 0.01337 M/sec
Rate of the formation of NH2Br = 0.0134 M/sec
The answer is C
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