Question

You play two games against the same opponent. The probability you win the first game is...

You play two games against the same opponent. The probability you win the first game is 0.70 If you win the first​ game, the probability you also win the second is 0.50 If you lose the first​ game, the probability that you win the second is 0.20 Complete parts​ a) through​ e).

a. Are the two games independent?

b. What's the probability you lose both games?

c. What's the probability you win both games?

d. Let random variable X be the number of games you win. Find the probability model for X complete the table below (hint: use your answers in part b and c)

e. Find and interpret the expected value of X?

f. What is the standard deviation of X?

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Answer #1

a.

Two games are not independent as probability of winning or losing a game is affected by the previous game played.

b.

Probability that you lose both games = Probability that you lose first game * Probability that you lose second game

Probability that you lose first game = 1 - Probability that you win first game = 1- 0.70 = 0.30

Probability that you lose second game = Probability of losing second game given that you lost first game

= 1 - Probability of winning when you lost first game = 1 - 0.20 = 0.80

Probability that you lose both games = Probability that you lose first game * Probability that you lose second game =

= 0.30*0.80 = 0.24

c.

Probability that you win both games = Probability that win lose first game * Probability that you win second game

Probability that you win first game = 0.70

Probability that you win second game = Probability of winning second game given that you won first game = 0.50

Probability that you win both games = Probability that you win first game * Probability that you win second game =

= 0.70*0.50 = 0.35

d.

X can take value 0 , 1 , 2

Probability of winning 0 games = Probability of losing both games = 0.24

Probability of winning 1 game = Probability of winning first game * Probability of losing second game + Probability of losing first game * Probability of winning second game

Here,

Probability of winning first game = 0.70

Probability of losing second game given that you won first game = 1 - Probability of winning second game = 1 -0.50 = 0.50

Probability of losing first game = 1 -0.70 = 0.30

Probability of winning second game given that you lost first game = 0.20

So,

Probability of winning 1 game = 0.70*0.50 + 0.30*0.20 = 0.35+0.06 = 0.41

Probability of winning 2 games = Probability of winning both games = 0.35

So, probability model for X is :

X 0 1 2
P(X=x) 0.24 0.41 0.35

e.

Expected value of X :

x P(X x)=0 0.241 0.41 2 0.35 1.11 E(X) -0,1,2

f.

Standard deviation of X :

2 SD(X) 322P(X - P(X) r-0,1,2 -0,1,2

V02 0.2412 0.4122 0.35 (1.11)2 V1.81 1.112 0.76

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