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You play two games against the same opponent. The probability you win the first game is 0.8. If you win the first game, the p

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Answer #1

a)
Option B

b)
Probability of losing both games = (1-0.8)*(1-0.4) = 0.12

c)
probability of winning both games = 0.8*0.6 = 0.48

d)
P(X = 0) = 0.12
P(X = 1) = 0.8*0.4 + 0.2*0.4 = 0.4
P(X = 2) = 0.48

e)
E(X) = 0*0.12 + 1*0.4 + 2*0.48 = 1.36

Var(X) = (0 - 1.36)^2*0.12 + (1 - 1.36)^2*0.4 + (2 - 1.36)^2*0.48
= 0.4704

SD(X) = sqrt(0.4704) = 0.686

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